Agaseous mixture contains 434.0 torr h 2 ( g ) , 434.0 torr h2(g), 389.9 torr n 2 ( g ) , 389.9 torr n2(g), and 77.9 torr ar ( g ) . 77.9 torr ar(g). calculate the mole fraction, χ , χ, of each of these gases.

H₂: 0.48,  N₂: 0.43;  Ar: 0.09

Explanation:

First of all, sum all the pressures to know the total pressure in the mixture.

434 Torr + 389.9 Torr + 77.9 Torr = 901.8 Torr

Mole fraction = Pressure gas / Total Pressure

Mole Fraction H₂: 434 Torr /901.8 Torr = 0.48

Mole Fraction N₂: 389.9 /901.8 Torr =0.43

Mole Fraction Ar:  77.9 /901.8 Torr = 0.09

Remember: SUM OF MOLE FRACTION = 1

the dependant variable is spilled water

the independent is the heat

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