Chemistry, 03.12.2019 06:31 Alreef8468

If nitrogen, with an oxidation state of -3, undergoes a synthesis reaction with h2, which has an oxidation state +1, what balanced equation shows the product formed?

2nh → n2 + h2
n2 + h2 → n2h2
2nh3 → n2 + 3h2
n2 + 3h2 → 2nh3

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Answer from: rileyw252

N₂ + 3H₂ → 2NH₃

Explanation:

Nitrogen react with hydrogen and form ammonia. The one mole of nitrogen gas react with two moles of hydrogen and form two moles of ammonia.

The oxidation state of nitrogen is -3 while that of hydrogen is +1. That's why two balance the charge one with one nitrogen atom three hydrogen atom react and with two nitrogen atom with a charge of -6 six hydrogen atoms are attached (+6).

Chemical equation:

N₂ + H₂ → 2NH₃

Balanced chemical equation;

N₂ + 3H₂ → 2NH₃

Answer from: Quest

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is $1s^{2}2s^{2}2p^{6}3s^{1}$ and electronic configuration of phosphorous is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{3}$ .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

$3na + p \rightarrow na_{3}p$

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.

Electrons are transferred from atoms of to atoms of this transfer makes the sodium atoms and the

Answer from: Quest

in scientific notation, the value of the speed of light in a vacuum

will be written as 2.995 * 10^8. when this value is represented in the form of

a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.

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If nitrogen, with an oxidation state of -3, undergoes a synthesis reaction with h2, which has an oxi...

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