What is the pressure of 0.540 mol of an ideal gas at 35,5 l and 223 k?
use pv = nrt and r= 8.314 okpa
molok
0.715 kpa
2.45 kpa
28.2 kpa
62.7 kpa
mark this and return

P = 28.2 Kpa

Explanation:

Given data:

Volume = 35.5 L

Temperature = 223 K

Number of moles = 0.540 mol

R = 8.314 Kpa. L/mol.K

Pressure = ?

Solution:

PV = nRT

P = nRT / V

P = 0.540 mol . 8.314 Kpa. L/mol.K .223 K / 35.5 L

P = 1001.2 Kpa . L /35.5 L

P = 28.2 Kpa

answer: value for at is 1.61\times 10^{9}.

solution:

given:

since, hcn is an acid , as it gives hydronium ion in its solution.

for hcn

is a base which accepts of hydronium ions.

as the reaction has reversed the k' of the new reaction will be inverse of k of previous reaction.

since   is acting as a base so the value of will be :