Answers: 2
![kb = \frac{[RNH_{4}^+][OH^-]}{[NH_{3}]}](/tpl/images/0401/7639/b9aa4.png)
:![4,004x10^{-5} = \frac{[RNH_{4}^+][2,34x10^{-5}]}{[NH_{3}]}](/tpl/images/0401/7639/cd1a3.png)
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The k b kb for an amine is 4.004 × 10 − 5 . 4.004×10−5. what percentage of the amine is protonated i...
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