Consider the reaction: co2(g) + ccl4(g) ⇌ 2 cocl2(g) δg° = 46.9 kj under the following conditions at 25 oc: latex: p_{co_2}p c o 2= 0.459 atm, latex: p_{ccl_4}p c c l 4= 0.984 atm, and latex: p_{cocl_2}p c o c l 2= 0.653 atm, δg for the reaction is , and the forward the reaction is

Answer : The value of is,

Explanation :

The formula used for is:

  ............(1)

where,

= Gibbs free energy for the reaction

=  standard Gibbs free energy  = 46.9 kJ

R = gas constant = 8.314 J/mole.K

T = temperature =

= equilibrium constant

First we have to calculate the value of .

The given balanced chemical reaction is,

The expression for reaction quotient will be :

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

Now we have to calculate the value of by using relation (1).

Now put all the given values in this formula, we get:

Therefore, the value of is,

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