How many moles of na2so4, are produced from 7.00 moles of (nh4)2so4?

The number of mole in the compounds are:

A. 6.60 g of (NH₄)₂SO₄ contains 0.05 mole.

B. 4.5 kg Ca(OH)₂ contains 60.81 moles

The mole of a substance is related to its mass and molar mass according to the equation:

With the above formula, we can obtain the answer to the questions given above. This is illustrated below:

A. Determination of the number of mole in  6.60 g of (NH₄)₂SO₄

Molar mass of (NH₄)₂SO₄ = 2[14 + (4×1)] + 32 + (4×16)

= 2[14 + 4] + 32 + 64

= 2[18] + 32 + 64

= 36 + 32 + 64

= 132 g/mol

Mass of NH₄)₂SO₄ = 6.60 g

Mole of NH₄)₂SO₄ =?

Mole of NH₄)₂SO₄ =

Mole of NH₄)₂SO₄ = 0.05 mole

Thus, 6.60 g of (NH₄)₂SO₄ contains 0.05 mole.

B. Determination of the number of mole in 4.5 kg Ca(OH)₂

Molar mass of Ca(OH)₂ = 40 + 2(16 + 1)

= 40 + 2(17)

= 40 + 34

= 74 g/mol

Mass of Ca(OH)₂ = 4.5 kg

= 4.5 × 1000

= 4500 g

Mole of Ca(OH)₂ =?

Mole of Ca(OH)₂ =

Mole of Ca(OH)₂ = 60.81 moles

Thus, 4.5 kg Ca(OH)₂ contains 60.81 moles

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