10. what mass of glass (cp = 0.749 j/gºc) is needed to absorb 5.00x104 j of heat, if it starts at 26.0 c and has a final temperature of 275.0°c?

m = 0.03  × 10⁴ g

Explanation:

Given data:

Specific heat capacity = 0.749 j/g.°C

Heat absorbed = 5.0 × 10⁴ J

Initial temperature = 26.0 °C

Final temperature = 275.0 °C

Mass = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT  = T2-T1

ΔT  = 275.0 °C - 26.0 °C

ΔT  = 249  °C

Q = m.c. ΔT

m = Q / c. ΔT

m =  5.0 × 10⁴ J / 0.749 j/g.°C  × 249  °C

m =  5.0 × 10⁴ J / 186.5  j/g

m = 0.03  × 10⁴ g

c is the answer because when something is left after something evaporates that shows the chemical change.

water at room temperature is flowing through a pipe with pressure taps located 10 ft apart along one section of the pipe, which are connected to a mercury (s=13.6) manometer.