In a nuclear reaction, the energy released is equal to 8.1 x 1016 joules. calculate the mass lost in this reaction. (1 j = 1 kg m2/s2) and the speed of light = 3.00 × 10^8 m/s ]

answer

7.2 x 1032 kg

2.7 x 108 kg

9.0 x 10-1 kg

7.2 x 10-16 kg

Answer : The mass lost in this reaction will be,

Explanation :

According to the Einstein equation, the energy is equal to the product of mass and the square of the speed of light.

The mathematical expression is :

where,

E = energy  released =

c = speed of light =

m = mass lost = ?

Now put all the given values in the above formula, we get the mass lost in the reaction.

Therefore, the mass lost in this reaction will be,

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.