When 50.0 cm^3 of 2.0 m hcl was added to 50.0 cm^3 of 2.0 m naoh solution in a simple calorimeter, there was a rise in temperature of 13.0°c . (assume that the specific heat capacity and density of the solution are 4.2j g^-1 k^-1 and 1.0 g cm^-3 respectively.) (a) calculate the enthalpy change of neutralization for one mole of water formed (solved : -1201.2 kj mol^-1) (b) what would be the temperature rise if 100.0 cm^3 of 2.0 m hcl were added to 100.0 cm^3 of 2.0 m naoh solution? explain your answer with the aid of calculations

120,630,890

step-by-step explanation:

110+10=120,620+10=630,880+10=890

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

the answer is b because, investigating whether another species of moth also drinks tears might be interesting, but it would not directly explain why this species of moth does.

to explain why this species of moth drinks tears, the scientist could ask: "what nutrients that moths need are in elephant tears? "

the scientist could experiment with moth repellent or oter ways to keep the moths away, but that would not answer his original question.