Asolution is made by mixing exactly 500 ml of 0.156 m naoh with exactly 500 ml of 0.100 m ch3cooh. calculate the equilibrium concentration of the species below. ka of ch3cooh is 1.8 × 10−5

[h+]

× 10 m
enter your answer in scientific notation.

[oh−]

m

[ch3cooh]

× 10 m
enter your answer in scientific notation.

[na+]

m

[ch3coo−]

m

The hydrogen ion concentration is .

Explanation:

From the given,

Volume of NaOH = 500 ml = 0.500L

Moarity of NaOH = 0.156M

The number of moles of NaOH is calculated is a follows.

Substitute the given values.

Volume of = 500 ml = 0.500L

Moarity of = 0.100M

The number of moles of is calculated is a follows.

Substitute the given values.

NaOH is a strong electrolyte

The number of moles NaOH left in the solution is

Therefore, hydroxide ion concentration is 0.028 mol

The hydrogen concentration

Therefore, hydrogen ion concentration is ,

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.