The stopcock connecting a 2.25 l bulb containing oxygen gas at a pressure of 4.00 atm, and a 5.25 l bulb containing neon gas at a pressure of 8.00 atm, is opened and the gases are allowed to mix. assuming that the temperature remains constant, what is the final pressure of the system in atm?

The final pressure of the system is 6.8 atm

Explanation:

Step 1: Data given

The oxygen bulb has a volume of 2.25L and pressure of4.00atm

The neon bulb has a volume of 5.25 L and a pressure if 8.00 atm

Step 2: Calculate the total volume

V1 + V2 = Vtotal

2.25 L + 5.25 L = 7.50 L

So the volume increases to 7.50 liters

Step 3: Calculate the partial pressure of oxygen

P1V1 = P'V'

P' = P1V1/V'

 ⇒with P1 = 4.00 atm

 ⇒ with V1 = 2.25 L

⇒ with P' = TO BE DETERMINED

⇒ with V' = 7.5 L

P' = (4*2.25) / 7.5

P'  = 1.2 atm = partial pressure of oxygen

Step 4: Calculate partial pressure of neon

partial pressure of neon (8.00*5.25)/7.5 = 5.6 atm

Step 5: Calculate final pressure

The total pressure = 1.2atm + 5.6atm = 6.8 atm.

The final pressure of the system is 6.8 atm

the correct answer is:

a. formation of precipitation