The equilibrium constant, kc, for the following reaction is 5.10×10-6 at 548 k. nh4cl(s) nh3(g) + hcl(g) calculate the equilibrium concentration of hcl when 0.564 moles of nh4cl(s) are introduced into a 1.00 l vessel at 548 k.[hcl] = m

The equilibrium concentration of HCl is

Explanation:

We are given:

Moles of = 0.564 moles

Volume of vessel = 1.00 L

Molarity is calculated by using the equation:

Molarity of

The given chemical equation follows:

Initial:         0.564

At eqllm:     0.564-x          x              x

The expression of for above equation follows:

The concentration of pure solid and pure liquid is taken as 1.

We are given:

Putting values in above equation, we get:

Negative sign is neglected because concentration cannot be negative.

So,

Hence, the equilibrium concentration of HCl is

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