Consider the following reaction at 298 k:

2h2(g) + o2(g) --> 2h2o(g) deltah= -483.6 kj

calculate the following quantities.

delta s sys=
delta s surr=
delta s univ=

Answer :

= -1622.8 J/K

= -94.6 J/K

= 0 J/K

Explanation :  Given,

= -483.6 kJ

The given chemical reaction is:

First we have to calculate the value of .

Entropy of system = -1622.8 J/K

As we know that:

Entropy of system = -Entropy of surrounding = 1622.8 J/K

and,

Entropy of universe = Entropy of system + Entropy of surrounding

Entropy of universe = -1622.8 J/K + (1622.8 J/K)

Entropy of universe = 0

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer