Asealed vessel contains 0.200 mol of oxygen gas, 0.100 mol of nitrogen gas, and 0.200 mol of argon gas. the total pressure of the gas mixture is 5.00 atm. the partial pressure of the argon

(a) 0.200 atm
(b) 0.500 atm
(c) 1.00 atm
(d) 2.00 atm
(e) 5.00 atm

D

Explanation:

We can use the mole ratio to calculate the partial pressure. The total number of moles is 0.2 + 0.2 + 0.1 = 0.5 moles

Now, we know that the mole fraction of the argon gas would be 0.2/0.5

The partial pressure is as follows. To calculate this, we simple multiply the number of moles by the total pressure.

0.2/0.5 * 5 = 1.0/0.5 = 2.00atm

D

first one is the correct answer

its going to be mutualism cuz they both benefit from the relationship.

~batmans wife dun dun