In the determination of iron in an ore, the ore (mostly fe2o3) is first dissolved in hcl(aq). a slight excess of sn2 is added to reduce fe3 to fe2 . enter the net ionic equation for the redox reaction.

2Fe⁺³ + Sn₂ → 2Fe⁺² + 2Sn⁺²

Explanation:

A redox reaction occurs between a compound that loses electrons and others that gain an electron. The first is being oxidized, and the other is being reduced.

In this situation, in the compound Fe₂O₃, the iron, has an oxidation number equal to +3, so it's Fe⁺³, and it will gain 1 electron to become Fe⁺². Because it was first dissolved in HCl, we must use the ion at the equation. The other compound Sn₂ will be oxidized to Sn⁺², so it will need to lose 2 electrons.

So, it will be necessary 2 Fe⁺³ for this reaction happen:

2Fe⁺³ + Sn₂ → 2Fe⁺² + 2Sn⁺²

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

24

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