You may want to reference (pages 906 - 909) section 19.5 while completing this problem. standard reduction half-cell potentials at 25∘c half-reaction e∘ (v) half-reaction e∘ (or) au3+(aq)+3e−→au(s) 1.50 fe2+(aq)+2e−→fe(s) −0.45 ag+(aq)+e−→ag(s) 0.80 cr3+(aq)+e−→cr2+(aq) −0.50 fe3+(aq)+3e−→fe2+(aq) 0.77 cr3+(aq)+3e−→cr(s) −0.73 cu+(aq)+e−→cu(s) 0.52 zn2+(aq)+2e−→zn(s) −0.76 cu2+(aq)+2e−→cu(s) 0.34 mn2+(aq)+2e−→mn(s) −1.18 2h+(aq)+2e−→h2(g) 0.00 al3+(aq)+3e−→al(s) −1.66 fe3+(aq)+3e−→fe(s) −0.036 mg2+(aq)+2e−→mg(s) −2.37 pb2+(aq)+2e−→pb(s) −0.13 na+(aq)+e−→na(s) −2.71 sn2+(aq)+2e−→sn(s) −0.14 ca2+(aq)+2e−→ca(s) −2.76 ni2+(aq)+2e−→ni(s) −0.23 ba2+(aq)+2e−→ba(s) −2.90 co2+(aq)+2e−→co(s) −0.28 k+(aq)+e−→k(s) −2.92 cd2+(aq)+2e−→cd(s) −0.40 li+(aq)+e−→li(s) −3.04 part a use the tabulated electrode potentials to calculate k for the oxidation of tin by h+ (at 25 ∘c): sn(s)+2h+(aq)→sn2+(aq)+h2(g) express your answer using two significant figures. kk = previous answer request answer incorrect; try again; 5 attempts remaining provide feedback incorrect. incorrect; try again; 5 attempts remaining. no additional feedback.