When a metal was exposed to light at a frequency of 3.64× 1015 s–1, electrons were emitted with a kinetic energy of 5.80× 10–19 j. what is the maximum number of electrons that could be ejected from this metal by a burst of light (at some other frequency) with a total energy of 8.66× 10–7 j?

Answer :  The maximum number of electrons released

Explanation : Given,

Frequency =

Kinetic energy =

Total energy =

First we have to calculate the work function of the metal.

Formula used :

where,

K.E = kinetic energy

h = Planck's constant =

= frequency  

w = work function

Now put all the given values in this formula, we get the work function of the metal.

By rearranging the terms, we get

Therefore, the works function of the metal is,

Now we have to calculate the maximum number of electrons released.

The maximum number of electrons released =

Therefore, the maximum number of electrons released is

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.