Which of the following is in the correct order of boiling points for nano₃, ch₃oh, c₂h₆, and ne? a) ne < ch₃oh < c₂h₆ < nano₃
b) nano₃ < ch₃oh < c₂h₆ < ne
c) ne < c₂h₆ < nano₃ < ch₃oh
d) ne < c₂h₆ < ch₃oh < nano₃
e) c₂h₆ < ne < ch₃oh < nano₃

D

Explanation:

Me has the least boiling point because it has the weakest degree of intermolecular forces. The weak van Der Waals forces exist in C2H6. In CH3OH, there are strong hydrogen bonds which accounts for the higher boiling point. NaNO3 is an ionic compound, hence it has the highest boiling point among all the substances mentioned.

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.