The vapor pressure of pure water at 15 °c is 12.8 mm hg. what is the equilibrium vapor pressure of water above a mixture of 72.0 g ethanol (ch3ch2oh, molar mass = 46.07 g/mol) and 22.0 g water?

The vapor pressure of water above this mixture is 5.6173 mm Hg.

Explanation:

We need to find the vapour pressure due to water in the solution.

According to Raoult's law ,

The vapour pressure due to any one component alone is the product of it's pure vapour pressure and it's mole fraction in the solution .

i.e ,

where ,

∴

∴

[tex]Y_A=0.43885*12.8\\Y_A=5.6173 mm Hg[tex]

The vapor pressure of water above this mixture is 5.6173 mm Hg.

plasma is the state of matter where the substance is ionized and has no definite shape or volume. the fact of being ionized makes the substance a good electrical conductor.

diaria maybe go see a doctor about that