Acertain substance condenses at a temperature of 123.3°c . but if a 65.0 gm sample of x is prepared with 24.6g of urea ((nh2)2co) dissolved in it, the sample is found to have a condensation point of 124.3°c instead.
1. calculate the molal boiling point elevation constant kb of x . round your answer to significant digits.

Kb = 0.159 °C.kg/mol

Explanation:

The condensation point has the same value than the boiling point. The elevation in the boiling point can be calculated using the following expression.

ΔT = Kb × b

where,

ΔT: elevation in the boiling point

Kb: molal boiling point elevation constant

b: molality of the solute

The molality of the urea is:

Then,

ΔT = Kb × b

(124.3°C-123.3°C) = Kb × (6.30 mol/kg)

Kb = 0.159 °C.kg/mol

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