425 ml of neon gas at -12°c and 788 mmhg
expands into a 2.40 l container while the
pressure decreases to 577 mmhg. what is the
temperature of the gas in °c?

806.23 °C

The question requires we calculate the new temperature of the gas in °C.

We are given;

When doing questions on gas law, we always use temperature in Kelvin.

K = °C + 273

Therefore, Initial temperature, T₁ =261 K

To calculate the new temperature, we are going to use the combined gas equation.

T₂ = P₂V₂T₁ /P₁V₁

Therefore;

T₂ = (577 mmHg × 2.4 L × 261 K) ÷ (788 mmHg × 0.425 L)

    = 1079.226 K

    = 1079.23 K

But, °C = K - 273

            = 1079.23 K - 273

Therefore, T₂ = 806.23 °C

Therefore, the new temperature is 806.23°C

it would be d. henry moseley

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answer: i have one answer

acids are substances that ionize (break off) in an aqueous solution to produce hydrogen (h+) ions

explanation:

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