When copper combines with oxygen, copper (ii) oxide is formed. if 7.0 mol of copper reacts with 4.0 mil of oxygen, what amount of the excess reactant remains?

I believe that there are .5 moles of O₂ left over.

Explanation: O₂+ 2 Cu= 2 CO₂+ 2 H₂O. With 7 moles of Cu you can get 7 moles of CuO. But, with 4 moles of O₂ you can get 8 moles of CuO, so O₂ is the limiting reactant. Thus, you would have to use 7 moles of Cu in order to determine the moles of O₂ and you get 3.5 moles of O₂. 4 moles- 3.5 moles =.5 moles

the child will have heterozygous dominant chromosomes as characters of his father are dominant over the characters of his mother.

the child is heterozygous

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm