Given the following amounts of gasses, calculate the number of moles of each gas. calculate the volume of each amount of gas would occupy at 100°c and 15atm.

a. 5.8g nh₃
b. 48g o₂
c. 10.8g he

a) V = 0.6958 L

b) V = 3.061 L

c) V = 0.0444L

Explanation:

a)  5.8 grams of NH3

step 1: Calculate moles of NH3

Moles NH3 = mass NH3 / molar mass of NH3

Moles NH3 = 5.8 grams / 17.03 g/mol

Moles NH3 = 0.341 moles

step 2: Calculate volume of NH3

p*V = n*R*T

V = (nRT)/p

V = (0.341 * 0.08206 * 373)/15

V =0.6958 L

b) 48g O2

step 1: Calculate moles of O2

Moles O2 = mass O2 / molar mass of O2

Moles O2 = 48 grams / 32 g/mol

Moles NH3 = 1.5 moles

step 2: Calculate volume of O2

p*V = n*R*T

V = (nRT)/p

V = (1.5 * 0.08206 * 373)/15

V =3.061 L

c) 10.8g He

step 1: Calculate moles of He

Moles He = mass He / molar mass of He

Moles He = 5.8 grams / 4g/mol

Moles He = 0.145 moles

step 2: Calculate volume of HE

p*V = n*R*T

V = (nRT)/p

V = (0.145 * 0.08206 * 373)/15

V =0.0444 L

d.) circle motion requires a force to give it a centripetal acceleration.

d.) the average kinetic energy of the gas particles is greater in container b because its particles move faster.