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calculate the energy of a gamma ray photon with a frequency of 6.0 x 10^22

E = 39.78 ×10⁻¹²  j

Explanation:

Given data:

Frequency of photon = 6.0×10²² s⁻¹

Energy of photon = ?

Solution:

Formula:

E = h.f

E = 6.63 ×10⁻³⁴ m² kg/s × 6.0×10²² s⁻¹

E = 39.78 ×10⁻¹² Kg. m²/s²

Kg. m²/s² = j

E = 39.78 ×10⁻¹²  j

a is the answer

explanation:

which statement about trans-fatty acids is false?

a. the conversion of cis-fatty acids to trans-fatty acids is inhibited by the presence of antioxidants.

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a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.