An element from group 2 will form ionic bonds with
a) any other metal.
b) all transition metals.
c) a nonmetal, groups 13-17.
d) any noble gas in group 18.

An element from Group 2 will form ionic bonds with a nonmetal, Groups 13-17

Explanation:

An ionic bond is formed between a "metal and non-metal". The valence electrons are lost in one and gained in the other atom. It involves electrostatic forces between the two ions which are of opposite charges.  

When one atom(metal) losses an electron, it becomes a "positive ion". Similarly, when the other atom(non-metal) gains an electron it becomes a negative ion. For example: The formation of NaF(Sodium Fluoride).

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explanation:

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.