Calculate the enthalpy of reaction for 2co + o2 → 2co2. given the following bond energies:
be(c≡o) = 1074 kj/mol
be(o≡o) = 499 kj/mol
be(c≡o) = 802 kj/mol

Answer : The enthalpy change for the reaction is 1043 kJ/mol.

Explanation :

The given chemical reaction is:

As we know that:

The enthalpy change of reaction = E(bonds broken) - E(bonds formed)

Given:

= 1074 kJ/mol

= 499 kJ/mol

= 802 kJ/mol

Now put all the given values in the above expression, we get:

Therefore, the enthalpy change for the reaction is 1043 kJ/mol.

the atomic number will stay the same no matter how many electrons it has, so it doesn’t decrease nor increase. it’ll only change with a different number of protons

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole