Which of the following is the correct order of steps in translation?

1. the ribosome translocates the trna in the a site to the p site and the empty trna in the p site is moved to the e site where it is released
2. the large ribosomal subunit attaches with the initiator trna with the amino acid methionine (met) located in the p site
3. a release factor, a protein shaped like an aminoacyl trna, promotes hydrolysis and releases the polypeptide
4. a small ribosomal subunit binds to a molecule of mrna5. the anticodon of an incoming aminoacyl trna base-pairs with the complementary mrna codon in the a site

4,2,1,3

Explanation:

4. A small ribosomal subunit binds to a molecule of mRNA5. the anticodon of an incoming aminoacyl tRNA base-pairs with the complementary mRNA codon in the A site.

2. The large ribosomal subunit attaches with the initiator tRNA with the amino acid methionine (Met) located in the P site.

1. The ribosome translocates the tRNA in the A site to the P site and the empty tRNA in the P site is moved to the E site where it is released.

3. A release factor, a protein shaped like an aminoacyl tRNA, promotes hydrolysis and releases the polypeptide.

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explanation:

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.