Calculate the number of grams of carbon dioxide produced from complete combustion of one liter of octane by placing the conversions in the correct order. make sure the units of adjacent conversion factors cancel out. 1 l octane times times times times times = 2171 g carbon dioxide

15.71g

Explanation:

The general combustion equation for all hydrocarbons is

CxHy + (x+y/4) O2 = xCO2 + (y/2) H2O

For octane, C8H18 :

C8H18 + ( 8 + 18/4 ) O2 = 8CO2 + 9H2O

C8H18 + 50/4 O2 = 8CO2 + 9H2O

C8H18 + 25/2 O2 = 8CO2 + 9H2O

2C8H18 + 25 O2 = 16 CO2 + 18H2O (balanced)

From the balanced equation,

2 x 22.4 L of octane produced 16 [ 12 + (16 x 2)] of carbon dioxide

That is,

44.8 L of octane produced 704g of carbon dioxide

So, 1L of octane will produce 1 L x 704g/44.8 L = 15.71g of carbon dioxide

Therefore, 15.71g of carbon dioxide will be produced by the complete combustion of 1 L of octane.

by cartels in other countries, shipped by air, mail, or land. i cant really see your answer choices : /

the answer for sodium is 0.186

the answer for rubidium is 0.251