Explain how an ionic compound forms between na & n.

na atom(s) each lose electron(s), ion(s). atom(s) gains (s), forming a ion. the ions attract, forming na3n

Three Na atom(s) each lose one electron, forming three Na+ ions. One N atom gains three electrons, forming a N^-3 ion. The ions attract, forming Na3N

Explanation:

Three Na atom(s) each lose one electron, forming three Na+ ions. One N atom gains three electrons, forming a N^-3 ion. The ions attract, forming Na3N.

Ionic bond:

It is the bond which is formed by the transfer of electron from one atom to the atom of another element.  

Both bonded atoms have very large electronegativity difference. The atom with large electronegativity value accept the electron from other with smaller value of electronegativity.

For example:

Na₃N is ionic compound. The electronegativity of is 3.04 and for sodium is 0.93. There is large difference is present. That's why electron from sodium is transfer to the nitrogen. Sodium becomes positive and nitrogen becomes negative ion.

One nitrogen atom required three electrons to complete the octet while sodium have one valance electron that's why three sodium atoms combine with one nitrogen atom.

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.