I’ll mark ubr /> what is the percent yield for the reaction below when 364 g so2 and 42.0 g
o2 produce 408 g so3?
2802(g) + o2(9) ► 2503(9)
a. 51.5%
ob. 89.7%
o c. 97.1%
o d. 100%

Percent yield = 196%

Explanation:

Given data;

Mass of SO₂ = 364 g

Mass of O₂ = 42.0 g

Mass of SO₃ = 408 g

Percent yield = ?

Solution:

Chemical equation:

2SO₂ + O₂ → 2SO₃

Number of moles of SO₂:

Number of moles = mass/ molar mass

Number of moles = 364 g / 64.066 g/mol

Number of moles = 5.7 mol

Number of moles of oxygen:

Number of moles = mass/ molar mass

Number of moles = 42.0 g / 32 g/mol

Number of moles = 1.3 mol

Now we compare the moles ammonia with hydrogen and nitrogen

                              O₂              :      SO₃

                                1               :        2

                                1.3            :      2/1 ×1.3 = 2.6 mol                                 

                              SO₂           :        SO₃

                                  2            :        2

                                  5.7          :      5.7

The number of moles of  SO₃ produced by oxygen are less so it will limiting reactant.

Theoretical yield:

Mass = number of moles × molar mass

Mass = 2.6 mol × 80.07 g/mol

Mass = 208.2 g

Percent yield:

Percent yield = actual yield / theoretical yield × 100

Percent yield = 408 g / 208.2 g × 100

Percent yield = 1.96 × 100

Percent yield = 196%

because u need two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei to form isotopes.

so since they all have the same shape? i mean maybe because m& m and reeses are both chocolates