Tantalum (ta; density = 16.634 g/cm^3 and molar mass = 180.9479 g/mol) has a body-centered cubic structure with a unit-cell edge length of 3.3058 å. use these data to calculate the volume of the tantalum unit cell, the mass of a tantalum unit cell, the number of tantalum atoms in a unit cell, and the number of tantalum atoms in one mole (according to the data presented here).

V = 3.6127x10⁻²³cm³

mass = 6.009x10⁻²²g

2 atoms

6.022x10²³ atoms in 1 mole

Explanation:

The volume of the unit cell is the lenght to the third power.

V = (3.3058x10⁻¹⁰ m )³ = 3.6127x10⁻²⁹m³× (1x10⁶cm / 1m) = 3.6127x10⁻²³cm³

Using density, mass of  a talantalum unit cell is:

3.6127x10⁻²³cm³×(16.634g/cm³)= 6.009x10⁻²²g

As the unit cell is body-centered cube, atoms in an unit cell are:

2 atoms per 6.009x10⁻²²g, 180,9479g (1 mole) contains:

180,9479g × (2atoms / 6.009x10⁻²²g) = 6.022x10²³ atoms in 1 mole

I hope it helps!

43.452

step-by-step explanation:

284 times .153 = 43.452

nacl is added to the aqueous of what? ? in order to get a proper answer you have to specify the exact composition of the aqueous solution.