Synthesis of the activated form of acetate (acetyl‑coa) is carried out in an atp‑dependent process. acetate+coa+atp⟶acetyl−coa+amp+ppi acetate+coa+atp⟶acetyl−coa+amp+ppi the δ′∘δg′∘ for the hydrolysis of acetyl‑coa to acetate and coa is −32.2 kj/mol−32.2 kj/mol , and that for hydrolysis of atp to amp and ppippi is −30.5 kj/mol−30.5 kj/mol . calculate ? g’o for the atp –dependent synthesis of acetyl-coa.

of the reaction is 1.7 kJ/mol.

Hydrolysis of the pyrophosphate shifts the equilibrium of the reaction to the right, making the formation of acetyl-CoA energetically more favorable.

Explanation:

The synthesis of acetyl CoA is as follows.

Form the given data,

Total the above two steps we get,

Therefore, of the reaction is 1.7 kJ/mol.

According to the Lechatelier's principle, a system at equilibrium always shows a tendency to regain the state of equilibrium., if equilibrium disturbed by an external factor only.

The enzyme inorganic pyrophosphotase catalyze the reaction.

The enzyme removes the ppi , one of the product in acetyl -CoA  reaction.

This would disturb the equilibrium therefore, system try to regain the state of equilibrium. And the equilibrium shifted to the right side.

Therefore, Hydrolysis of the pyrophosphate shifts the equilibrium of the reaction to the right, making the formation of acetyl-CoA energetically more favorable.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

the answer is symmetrical : )