Calculate the ph of a 0.208 0.208 m solution of ethylenediamine ( h 2 nch 2 ch 2 nh 2 h2nch2ch2nh2). the p k a pka values for the acidic form of ethylenediamine ( h + 3 nch 2 ch 2 nh + 3 h3+nch2ch2nh3+) are 6.848 6.848 ( p k a1 pka1) and 9.928 9.928 ( p k a2 pka2). ph = ph= calculate the concentration of each form of ethylenediamine in this solution at equilibrium.

[ h 2 nch 2 ch 2 nh 2 ] =
[h2nch2ch2nh2]= m m
[ h 2 nch 2 ch 2 nh + 3 ] =
[h2nch2ch2nh3+]= m m
[ h + 3 nch 2 ch 2 nh + 3 ] =
[h3+nch2ch2nh3+]=

Why do you suppose the structural polysaccharide cellulose does not contain branches? why do you suppose the structural polysaccharide cellulose does not contain branches? branches in the molecule would generate side chains that would almost certainly make it difficult to pack the cellulose molecules into globules, thereby decreasing the flexibility and strength of the globules. branches in the molecule would generate side chains that would almost certainly make it difficult to pack the cellulose molecules into microfibrils, thereby increasing the rigidity and strength of the microfibrils. branches in the molecule would generate side chains that would almost certainly make it difficult to pack the cellulose molecules into globules, thereby increasing the flexibility and strength of the globules. branches in the molecule would generate side chains that would almost certainly make it difficult to pack the cellulose molecules into microfibrils, thereby decreasing the rigidity and strength of the microfibrils.

The blackbody curve for a star name zeta is shown below. what is the peak wavelength for this star ?

Which statement best explains the relationship between an area is geography and the temperature of its surface water