How many grams of brcl form when 239.7g cl2 react with excess br2

Mass = 1568.9 g

Explanation:

Given data:

Mass of Cl₂ = 239.7 g

Mass of BrCl form = ?

Solution;

Chemical equation;

Cl₂ + Br₂ →  2BrCl

Number of moles of Cl₂:

Number of moles = mass / molar mass

Number of moles = 239.7 g/ 35.5 g/mol

Number of moles =  6.8 mol

Now we will compare the moles of Cl₂ and BrCl.

                          Cl₂      :         BrCl

                            1       :            2

                         6.8      :        2×6.8 mol = 13.6 mol

Mass of BrCl:

Mass = number of moles × molar mass

Mass = 13.6 mol × 115.357 g/mol

Mass = 1568.9 g

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