Chemistry, 16.12.2019 19:31 ThatOneGuy8144

Agas mixture contains hbr, no2, and c2h6 at stp. if a tiny hole is made in the container, which gas will effuse fastest? which gas molecules have the highest average kinetic energy at this temperature?

Answers: 2

Show answers

Answers

Answer from: mccay5016987

Explanation:

Molar mass of HBr = 81 g/mol

Molar mass of nitrogen dioxide gas = 46 g/mol

Molar mass of ethane = 30 g/mol

Graham's Law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

So, the gas with least molar mass will effuse out fastest from the container and that is ethane gas.

The formula for average kinetic energy is:

$K.E=\frac{3}{2}kT$

where,

k = Boltzmann’s constant = $1.38\times 10^{-23}J/K$

T = temperature = 273.15 K ( at STP)

As we can see from the formula that kinetic energy depends upon only temperature of the gas molecule.

So, from this we can say that all the gas molecules have the same average kinetic energy at this temperature.

Answer from: josmanu235

If a tiny hole is made in a container with a gas mixture of HBr. NO₂ and C₂H₆ at STP, C₂H₆ will effuse fastest and they will all have the same average kinetic energy.

We have a gas mixture containinig HBr, NO₂, and C₂H₆ at STP, and a tiny hole is made in the container. The gases will experience effusion, which refers to the movement of gas particles through a small hole. According to Graham's Law, the effusion rate of a gas is inversely proportional to the square root of the mass of its particles. Considering the molar masses of HBr (80.91 g/mol), NO₂ (46.00 g/mol) and C₂H₆ (30.07 g/mol), we can predict that C₂H₆, with the lowest molar mass, will have the highest effusion rate.

On the other hand, we can calculate the average kinetic energy of a gas (KE) using the following expression.

$KE = \frac{3}{2} kT$

where,

k: Boltzmann’s constant (1.38 × 10⁻²³ J/K)T: absolute temperature (standard temperature: 273.15 K)

As we can see, the average kinetic energy of a gas depends only on the temperature. For the 3 gases at STP is:

$KE = \frac{3}{2} (1.38 \times 10^{-23} J/K)(273.15K)= 5.65 \times 10^{-21} J$

If a tiny hole is made in a container with a gas mixture of HBr. NO₂ and C₂H₆ at STP, C₂H₆ will effuse fastest and they will all have the same average kinetic energy.

You can learn more about effusion here:

Answer from: Quest

Ais stronge

Answer from: Quest

50.23 i believe is correct but don't quote me on that.

Another question on Chemistry

Chemistry, 21.06.2019 23:00

Esign techniques and materials that reduce the negative environmental impact of a structure are referred to as

Answers: 3

Answer

Chemistry, 22.06.2019 03:30

Nanotechnology, the field of trying to build ultrasmall structures one atom at a time, has progressed in recent years. one potential application of nanotechnology is the construction of artificial cells. the simplest cells would probably mimic red blood cells, the body's oxygen transporters. for example, nanocontainers, perhaps constructed of carbon, could be pumped full of oxygen and injected into a person's bloodstream. if the person needed additional oxygen-due to a heart attack perhaps, or for the purpose of space travel-these containers could slowly release oxygen into the blood, allowing tissues that would otherwise die to remain alive. suppose that the nanocontainers were cubic and had an edge length of 24 nanometers. part a part complete what is the volume of one nanocontainer? (ignore the thickness of the nanocontainer's wall.) express your answer using two significant figures. v v = 1.4ă—10â’20 l previous answers correct significant figures feedback: your answer 1.3824â‹…10â’20 = 1.382ă—10â’20 l was either rounded differently or used a different number of significant figures than required for this part. if you need this result for any later calculation in this item, keep all the digits and round as the final step before submitting your answer. part b suppose that each nanocontainer could contain pure oxygen pressurized to a density of 81 g/l . how many grams of oxygen could be contained by each nanocontainer?

Answers: 3

Answer

Chemistry, 22.06.2019 03:40

Can someone me with questions 12 and 13 plz.

Answers: 3

Answer

Chemistry, 22.06.2019 04:40

Listen base your answer to the question on the information below.propane is a fuel that is sold in rigid, pressurized cylinders. most of the propane in a cylinder is liquid, with gas in the space above the liquid level. when propane is released from the cylinder, the propane leaves the cylinder as a gas. propane gas is used as a fuel by mixing it with oxygen in the air and igniting the mixture, as represented by the balanced equation below.c3h8(g) + 5o2(g) → 3co2(g) + 4h2o() + 2219.2 kja small amount of methanethiol, which has a distinct odor, is added to the propane to consumers detect a propane leak. in methanethiol, the odor is caused by the thiol functional group (–sh). methanethiol, ch3sh, has a structure that is very similar to the structure of methanol.what is the correct structural formula for a molecule of methanethiol

Answers: 3

Answer

You know the right answer?

Agas mixture contains hbr, no2, and c2h6 at stp. if a tiny hole is made in the container, which gas...

Questions