Roughly 0.0150% of the mass of ordinary water is due to "heavy water," in which one of the two hydrogen atoms in an h2o molecule is replaced with deuterium, 2h. how much average fusion power could be obtained if we "burned" all the 2h in 3.00 liters of water in 2.00 days by somehow causing the deuterium to fuse via the following reaction?

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explanation:

why?

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answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

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