Which of the following will cause the volume of an ideal gas to triple in value? a) raising the absolute temperature by a factor of 3 while increasing the pressure by a factor of 3.b) lowering the absolute temperature by a factor of 3 while increasing the pressure by a factor of 3.c) lowering the pressure by a factor of 3 while the temperature stays constant. d) lowering the absolute temperature by a factor of 3 at constant pressure. e) raising the temperature from 25 c to 75 c at constant pressure.

C) C) Lowering the pressure by a factor of 3 while the temperature stays constant.

Explanation:

P V = nRT ⇒  V = nRT/P

Volume is directly proportional to  n, T and inversely proportional to P

a) Vfinal  = n R (3TI ) /3Pi = nRTi/Pi = Vi                                  FALSE

b) Vinal = n R (Ti/3) /(3Pi) = nRTi/Pi = (1/9) Vinitial                  FALSE

c)  Vfinal = n R(Ti/3) / Pi = nRTi/Pi = Vi                                    TRUE  

d) Vfinal = nR(Tinitial/3P = 1/3 Vi                                             FALSE

e) False we do not use ªC in the ideal gas law, we use K    FALSE

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.