Aballoon with a volume of 1 l is filled with a gas that has a pressure of 4 pa. what is the new
pressure of the gas if the balloon is squeezed down to a volume of .6 l? (boyle's law, pg. 79) show work

P₂  =   6.67 Pa

Explanation:

Given data:

Initial volume = 1L

Initial pressure = 4 Pa

Final pressure = ?

Final volume = 0.6 L

Solution:

P₁V₁ = P₂ V₂

V₁ = Initial volume

P₁ = Initial pressure

V₂ = Final volume  

P₂ = Final pressure

Now we will put the values in formula.

P₁V₁ = P₂ V₂

P₂  =  P₁V₁ /V₂

P₂  =   4 Pa × 1 L / 0.6 L

P₂  =   6.67 Pa

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