For a galvanic cell that uses the following two half-reactions, cr2o72-(aq) + 14 h+(aq) + 6 e- → 2 cr3+(aq) + 7 h2o(l) pb(s) → pb2+(aq) + 2 ehow many moles of pb(s) are oxidized by three mol es of cr2o72-?

a) 3

b) 6

c) 9

d) 18

C

Explanation:

The detailed solution is found in the image attached. It is necessary to note that the oxidation half equation is multiplied by three to balance electron gain and loss. This is adequately shown in the image below. Inferences are only drawn from balanced redox reaction equation hence the first step is to balance the redox reaction equation.

Most likely a is the answer - because  you generate   38 atp's but also consume an atp.   each atp gives approx. less than 4 kcal so probably a is the closest answer.

Oh nskskakaaka