418 n force to move a 56 kg mass, at what rate does the object accelerate?

7.5 m/s²

Explanation:

Given data:

Force on object = 418 N

Mass of object = 56 kg

Acceleration rate = ?

Solution:

Definition:

The acceleration is rate of change of velocity of an object with respect to time.

Formula:

a = Δv/Δt

a = acceleration

Δv = change in velocity

Δt = change in time

Units:

The unit of acceleration is m.s⁻².

Acceleration can also be determine through following formula,

F = m × a

a = F/m

Now we will put the values.

a = 418 N/ 56 kg

N = Kg. m /s²

a = 418 Kg. m /s²/ 56 kg

a = 7.5 m/s²

particle   p is an electron and particle q is a neutron

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.