The vapor pressure of a substance is measured over a range of temperatures. a plot of the natural log of the vapor pressure versus the inverse of the temperature (in kelvin) produces a straight line with a slope of −3.58×103k. what is the enthalpy of vaporization of the substance? 29.8 kj/mol2.32×1023kj/mol0.431 kj/mol294 kj/mol

ΔHvap = 431 J/mol

Explanation:

The relation between the vapor pressure and the absolute temperature is given by the Clausius-Clapeyron equation.

where,

p: vapor pressure

ΔHvap: enthalpy of vaporization

T: absolute temperature

C: constant

We can see that this corresponds to a linear equation with slope -ΔHvap/R and intercept C. If the slope is -3.58 × 10³ K,

-3.58 × 10³ K = -ΔHvap/R

3.58 × 10³ K = ΔHvap/(8.314 J/K.mol)

ΔHvap = 431 J/mol

rosa was looking for patterns to predict the products of chemical reactions. she recorded three similar decomposition reactions in the table.she should record 2licl + 3o2.

in the last row of the table. it is the thermal decomposition of chlorate lithium, hence, she should record these products as: lithium chloride ( 2licl ) and oxygen ( 3o2 )   2 > 2 licl + 3o2.