The heating curve for a sample of pure ethanol shows the slope of the line for gaseous state is greater than the slope of the line for the liquid state.

which statement below explains that? a. the specific heat capacity of the gaseous ethanol is less than the specific heat capacity of liquid ethanol. b. the specific heat capacity of the gaseous ethanol is greater than the specific heat capacity of liquid ethanol. c. the heat of vaporization of ethanol is less than the heat of fusion of ethanol. d. the heat of vaporization of ethanol is greater than the heat of fusion of ethanol.

a. The specific heat capacity of the gaseous ethanol is less than the specific heat capacity of liquid ethanol.

Explanation:

The heating curve is a curve that represents temperature (T) in the y-axis vs. added heat (Q) in the x-axis. The slope is T/Q = 1/C, where C is the heat capacity. Then, the higher the slope, the lower the heat capacity. For a constant mass, it can also represent the specific heat capacity (c).

Heats of vaporization and fusion cannot be calculated from these sections of the heating curve.

Which statement below explains that?

a. The specific heat capacity of the gaseous ethanol is less than the specific heat capacity of liquid ethanol. YES.

b. The specific heat capacity of the gaseous ethanol is greater than the specific heat capacity of liquid ethanol. NO.

c. The heat of vaporization of ethanol is less than the heat of fusion of ethanol. NO.

d. The heat of vaporization of ethanol is greater than the heat of fusion of ethanol. NO.

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g