Zinc will react with hydrochloric acid to produce hydrogen gas. zn(s)+2hcl(aq)⟶zncl2(aq)+h2(g)what is the volume of h2 gas produced if 2.00g of zinc is used with an excess of hydrochloric acid in the reaction above at stp? round to 3 significant figures.

0.690 liters is the volume of hydrogen gas produced if 2.00 grams of zinc is used with an excess of hydrochloric acid.

Explanation:

Mole so zinc =

According to reaction, 1 mole of zinc gives 1 mole of hydrogen gas.

Then 0.03077  mole of zinc will give :

of hydrogen gas

Pressure of hydrogen gas ,P= 1 atm

Temperature  of of hydrogen gas ,T= 273.15 K

Volume of hydrogen gas = V = ?

Moles of hydrogen gas = 0.03077 mol

PV = nRT (Ideal gas equation )

V = 0.690 L

0.690 liters is the volume of hydrogen gas produced if 2.00 grams of zinc is used with an excess of hydrochloric acid.

answer: c.

explanation:

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