The naturally occurring isotopes of vanadium are vanadium-50 and vanadium-51. vanadium-50 has an abundance of 0.250% and a mass of 49.947 amu. vanadium-51 has an abundance of 99.750% and a mass of 50.944 amu. calculate the average atomic mass of vanadium.
a) 50.942 amu
b) 62.558 amu
c) 63.303 amu
d) 5094.151 amu

The answer to your question is letter A

Explanation:

                            Abundance              Atomic mass

       V-50             0.25%                         49.947

       V-51            99.750%                       50.944

Formula

Average atomic mass = [V-50-Abundance x V-50-Atomic mass] +

                                       [ V-51-Abundance x V-51-Atomic mass]

Substitution

Average atomic mass = [ 0.0025 x 49.947] + [0.9975 x 50.944]

                                    = 0.125 + 50.817

Result

                                    = 50.942 amu

the dependant variable is spilled water

the independent is the heat

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