Elaborate on how the duet and octet rules relate to ion formation?
a) the duet rule or the octet rule state that atoms form ions in an effort to acquire valence electron configuration impermanence.
b) both the duet and octet rules reveal that atoms gain or lose electrons forming ions to achieve a more stable electron configuration.
c) ion formation only occur if the atom have a full duet electron configuration or full octet electron configuration of valence electrons.
d) formation of immutable noble-gas configuration ions results from atoms with ambiguous duet or octet configurations of valence electrons.

B).Both the duet and octet rules reveal that atoms gain or lose electrons forming ions to achieve a more stable electron configuration.

Explanation:

Duet : The outermost shell of an element has two electron.

Octet : The outermost shell of an element has eight electron

According to Lewis Theory of bonding.

He suggested that atoms forms bond either by sharing of electron pair or by complete transfer of electron from one atom to other in order to achieve the stable atomic configuration.

Noble Gas configuration (stable atomic configuration) : When the outermost shell of an atom is fully filled(8 electron) , then it get stability and don't react with other element .E.g Ne = 10 electron = 1s(2) 2s(2) 2p(6) = 8 electron

Neon is stable elements.

Consider,Sodium element (Na) it has 11 electron = 1s(2) 2s(2) 2p(6) 3s(1) , If it looses 1 electron from 3s ,then it has 8 electron left (same as Ne).

So Na show (+1) valency .

Chlorine(Cl), it has 17 electron , 1s(2) 2s(2) 2p(6) 3s(2) 3p(5) , In order to achieve stability , it gain one electron and show (-1) valency.

d. temperate deciduous forest

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o