How many grams of mgcl, will be produced from 16.0 g of mg(oh), and 11.0 g of hcl?

a) from Mg(OH)2:

m MgCL2 = 26.121 g

b) from HCl:

m MgCl2 = 14.362 g

Explanation:

                          1 - Mg - 1

                          2 - Cl - 2

                          2 - O - 2

                          4 - H - 4

∴ Mw Mg(OH)2 = 58.3197 g/mol

∴ Mw HCl = 36.46 g/mol

∴ Mw MgCl2 = 95.211 g/mol

from Mg(OH)2:

⇒ m MgCL2 = (16.0 g Mg(OH)2)(mol Mg(OH)2/58.3197g)(mol MgCL2/mol Mg(OH)2)(95.211 g MgCl2/mol MgCl2) = 26.121 g MgCl2

from HCl:

⇒ m MgCL2 = (11 g HCl)(mol HCl/36.46g)(mol MgCl2/2 mol HCl)(95.211 gMgCl2/mol MgCl2) = 14.362 g MgCl2

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-