10g of hyrogen react with excess of oxygen gas according to the equation:
2h2+> 2h2o
what is the reacted volume of oxygen gas at stp and the mass of the produced water vapour in this reaction ?

Volume of O₂ = 56 dm³

mass of water vapors (H₂O) = 90 g

Explanation:

Data Given:

mass of Oxygen = 10 g

Volume of Oxygen = ?

mass of the water vapor = ?

Reaction Given:

                 2H₂+O₂>2H₂O

Solution:

First we have to look at the reaction for the information required

                 2H₂   +  O₂  > 2H₂O

               2 mol    1mol           2 mol

now convert moles to grams

molar mass of H₂ = 2(1) = 2 g/mol

molar mass of O₂ = 2(16) = 32 g/mol

molar mass of H₂0 = 2(1) + 16 = 18 g/mol

So the masses will be

                      2H₂          +              O₂        >      2H₂O

                2 mol (2 g/mol)      1mol (32 g/mol)         2 mol (18 g/mol)

                      4 g                            32 g                           36 g

So now we know that

4 g of hydrogen combine with 32 g of Oxygen and give 36 g of water vapors.

By using above information

First we find the volume of Oxygen:

For this first we find mass and then moles of Oxygen

As we know

if 4 g of hydrogen combine with 32 g of Oxygen then how much oxygen will react with 10 g of hydrogen

Apply unity formula

                        4 g of hydrogen H₂ ≅ 32 g of Oxygen O₂

                         10 g of hydrogen H₂ ≅ X g of Oxygen O₂    

by doing Cross multiplication

                         g of Oxygen O₂   = 32 g x 10 g / 4 g

                         g of Oxygen O₂   = 80 g

So,                  

mass of oxygen = 80 g

now find moles of oxygen

formula used:

            no. of moles = mass in grams/ molar mass . . . . . . (1)

Put values in above equation 1

            no. of moles = 80 g / 32 g/mol

             no. of moles = 2.5

Now to find volume of oxygen

Formula used

 Volume of O₂ = no. of moles x molar volume (22.4 dm³/ mol) . . . . . . (2)

Put values in equation 2

             Volume of O₂ = 2.5 moles x 22.4 dm³/mol

            Volume of O₂ = 56 dm³

Now to find mass of water vapors

As we now

if 4 g of hydrogen produce 36 g of water vapors then how much water vapor will produce from 10 g of hydrogen

Apply unity formula

                        4 g of hydrogen H₂ ≅ 36 g of water vapors (H₂O)

                         10 g of hydrogen H₂ ≅ X g of water vapors (H₂O)  

by doing Cross multiplication

                         g of water vapors (H₂O) = 36 g x 10 g / 4 g

                         g of water vapors (H₂O)   = 90 g

So,                  

mass of water vapors (H₂O) = 90 g

a rain shadow is a dry region of land on the side that is protected against the prevailing winds of a mountain range. the prevailing winds are the winds that occur most of the time in a particular place of the earth

prevailing winds carry air toward the mountain range. as the air rises up over a mountain range, the air cools, water vapor condenses, and clouds form. on this side of the mountains, called the windward side, precipitation falls in the form of  rain  or snow. this dry air produces a  rain shadow.

the answer is c i believe