34.62 ml of a 0.1510 m barium hydroxide solution was needed to neutralize 50.0 ml of a hydrochloric acidsolution. what is the concentration of the original hydrochloric acid solution?

0.104 M

Explanation:

For the titration of an acid and a base , the relation between the molarity and volume is as follows -

M₁V₁ = M₂V₂

where ,  

M₁ = concentration of acid ,  

V₁ = volume of acid ,

M₂ = concentration of base ,  

V₂ = Volume of base ,

from , the question ,  

M₁ = ?

V₁ = 50.0 mL

M₂ = 0.1510 M

V₂ = 34.62 mL

Using the above formula , the molarity of the stock solution , can be calculated as ,  

M₁V₁ = M₂V₂

M₁ * 50.0 mL  = 0.1510 M *  34.62 mL

M₁ = 0.1510 M *  34.62 mL / 50.0 mL

M₁ = 0.104 M

answer; ///i do believe that the correct answer is (b); ///particle composed of two or more atoms bonded together;

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).