When 1 mol each of c2h5oh and ch3co2h are allowed to react in 1 l of the solvent dioxane, equilibrium is established when 13 mol of each of the reactants remains. calculate the equilibrium constant for the reaction. (note: water is a solute in this reaction.)

Explanation:

The correct statement is:

When 1 mol each of C₂H₅OH and CH₃CO₂H are allowed to react in 1 L of the solvent dioxane, equilibrium is established when 1/3 mol of each of the reactants remains. Calculate the equilibrium constant for the reaction. (Note: Water is a solute in this reaction.)

1. Equilibrium equation

               ↑                  ↑                          ↑                    ↑

          ethanol     acetic acid        ethyl acetate       water

2. Equilibrium constant

Since water is also a solute in this reaction (the solvent is dioxane) its concentration will appear in the equilibrium constant.

3. Equlibrium concentrations:

Moles

                  C₂H₅OH + CH₃CO₂H     ⇄    CH₃CO₂C₂H₅ +   H₂O

Initial                1                  1                                 0                  0

Change          -2/3            -2/3                            +2/3             +2/3

End                  1/3               1/3                              2/3              2/3

Since the volume is 1 liter, the concentration is equal to the number of moles

4. Calculations:

the answer is 1 i believe