Methane (ch4) reacts with cl2 to yield ccl4 and hcl by the following reaction equation: ch4 + 4 cl2 → ccl4 + 4hcl. what is the δh of the reaction if 51.3 g of ch4 reacts with excess cl2 to yield 1387.6 kj?

The ΔH of the reaction if 51.3 g of reacts with excess to yield 1387.6 kJ is 432.27kJ

Explanation:

To calculate the moles, we use the equation:

moles of

As is present in excess, is the limiting reagent as it limits the formation of product.

If 3.21 moles of methane releases heat = 1387.6 kJ

Thus 1 mole of methane release=

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